The sum of three consecutive multiples of 8 is 888. Find the multiples

1.	The sum of three consecutive multiples of 8 is 888. Find the multiples.
Answer» ANSWER: LET 3 CONSECUTIVE multiples of 8 be 8x, 8(X+1), 8(x+2) -> By the given terms 8x + 8(x+1) + 8(x+2) = 888 8(x + x + 1 + x + 2)= 888 3x+3= 888 8 3x+3 = 111 3x=111-3 3x= 108 x= 108 3 x= 36 8x=36×8=288 8(x+1)= 8×36+1 =8+37 =296 8(x+2)=8×36+2 =8×36+2 =309 This is your answer hope it helps you please mark it as brainlyest...

The sum of three consecutive multiples of 8 is 888. Find the multiples.

Answer»

LET 3 CONSECUTIVE multiples of 8 be

8x, 8(X+1), 8(x+2)

-> By the given terms

8x + 8(x+1) + 8(x+2) = 888

8(x + x + 1 + x + 2)= 888

3x+3= 888

3x+3 = 111

3x=111-3

3x= 108

x= 108

x= 36

8x=36×8=288

8(x+1)= 8×36+1

=8+37

=296

8(x+2)=8×36+2

=8×36+2

=309