1.

The sum of three consecutive multiples of 8 is 888 find the multiples?​

Answer»

ANSWER:

let one MULTIPLE be y

other be y+8

THIRD be y+16

y+y+8+y+16

3y+21=888

3y = 888-21

3y = 867

y = 289

other TWO numbers are 297 and 305



Discussion

No Comment Found