The sum of three consecutive multiples of 11 is 663. Find it.

1.	The sum of three consecutive multiples of 11 is 663. Find it.
Answer» ong>Step-by-step explanation: LET the THREE CONSECUTIVE multiples of 11 be, x, (x+11), (x+22) Therefore, x+(x+11)+(x+22)=663 or, x+x+11+x+22=663 or, 3x=630 or, x=210 Since, x=210 Hence, x+11=221 and, x+22=232 I think there is some ERROR in the question. Nevertheless, if you want to know more about MATHEMATICS then you can visit my YouTube channel The name of my channel is Samanyu Pattanayak

Answer»

ong>Step-by-step explanation:

LET the THREE CONSECUTIVE multiples of 11 be,

x, (x+11), (x+22)

Therefore,

x+(x+11)+(x+22)=663

or, x+x+11+x+22=663

or, 3x=630

or, x=210

Since, x=210

Hence, x+11=221

and, x+22=232

I think there is some ERROR in the question.

Nevertheless, if you want to know more about MATHEMATICS then you can visit my YouTube channel

The name of my channel is

Samanyu Pattanayak

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The sum of three consecutive multiples of 11 is 663. Find it.

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