Saved Bookmarks
| 1. |
The sum of three consecutive multiple of 8 is 888 .find multiple |
|
Answer» Answer: Step-by-step EXPLANATION: → Let the first MULTIPLE of 8 be 8x. → Therefore the second consecutive multiple of 8 will be 8(x+1) → ALSO the third consecutive multiple of 8 will be 8(x+2). → It is given that the sum of these three consecutive MULTIPLES of 8 is 888 = 8x + 8(x+1) + 8(x+2) = 888 = 8x + 8x + 8 + 8x + 16 = 888 = 24x + 24 = 888 → Take 24 on the RHS = 24x = 888 - 24 = x = 864/24 = x = 36. → Therefore First multiple of 8 be 8x = 8 x 36 = 288 → Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296 → Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304 → If we sum up these three multiples i.e (288 + 296 + 304) we get 888. |
|