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The sum of three consecutive multiple of 11 is 363 find these multiple |
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Answer» Let US assume that the smallest multiple to be 11X, where x is any natural number. Hence, we can say the other NUMBERS are: 11(x+1) and 11(x+2) as they are consecutive multiples. So from he question: 11x+11(x+1)+11(x+2)=363 11x+11x+11+11x+22=363 33x+33=363 x+1=363/33 x+1=11 Therfore, x=10 On substituting the value of x in the numbers, 11x=110 11(x+1)=121 11(x+2)=132 |
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