Here is your SOLUTION Given:-sum of THREE consecutive even NUMBERS is 36LetNumber be X,x+2,x+4NowA/qx+(x+2)+(x+4)=363x+6=363x=36-63x=30x =10Hence Number are:-x=10x+2=10+2=12x+4=10+4=14The three consecutive even numbers are 10,12,14Hope it helps you
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