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The sum of three consecutive even integers is 108. What is the largest number? |
Answer» Let:-The three consecutive even numbers be 2x , 2x + 2 and 2x + 4 . Given:-SUM of these three consecutive even numbers = 108 Now on adding these three consecutive even numbers we GET ,=> 2x + (2x + 2) + (2x + 4) = 108 => 2x + 2x + 2x + 2 + 4 = 108 => 6x + 6 = 108 => 6(x + 1) = 108 =>x + 1 = 18 => x = 17 On putting the value of x in 2x , 2x +2 and 2x + 4 the numbers we have, => 2x = 2×17 = 34 => 2x + 2 = 2×17 + 2 = 36 => 2x + 4 = 2×17 + 4 = 38 Therefore:-The largest number is 38. |
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