1.

The sum of the squares of two consecutive odd positive integers is 394. Find them

Answer» LET the two NUMBERS are X and(x+2)

ACCORDING to the question (x) ^2+(x+2)^2=394

=>x^2+x^2+4x+4=394

=>2(x)^2+4x+4-394=0

=>2(x)^2+4x-390=0

=>2(x)^2+30x-26x-390=0

=>2x(x+15)-26(x+15)=0

=>(x+15)(2x-26)=0

=>x+15=0 or 2x-26=0

=>x= -15 orx=26/2=13

if x= -15,then x+2= -13

or

ifx=13,thenx+2=15


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