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The sum of the squares of two consecutive even numbers is 6500. Which is the smaller number?(a) 54 (b) 52(c) 48 (d) 56(e) None of these |
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Answer» (d) Let the two numbers be x and (x + 2). Then, x2 + (x + 2)2 = 6500 x2 + x2 + 4x + 4 = 6500 2x2 + 4x – 6496 = 0 x2 + 2x – 3248 = 0 x2 + 58x – 56x – 3248 = 0 (x + 58) (x – 56) = 0 x = 56 |
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