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| 1. |
The sum of the squares of the three consecutive natural numbers is 77 . Find the numbers |
| Answer» let the three numbers are x, x+1 and x+2.so (x)2+(x+1)2+(x+2)2\xa0= 77x2+x2+2x+1+x2+4x+4= 773x2+6x+5 = 773x2+6x -72 =03x2+18x-12x-72 =03x(x+6)-12(x+6)=0(3x-12)(x+6)=03x-12=0 or x+6 =03x=12 or x= -6x=12/3=4 nor x=-6x =4 , x=-6 is not possible because a natural number can not be negative.so numbers are 4,5 and 6.\xa0 | |