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The sum of the roots of equation kx^2-3x+9=0 is 3/5 then the product of roots istell step by step answer​

Answer»

GIVEN:-

  • f(x) = kx²-3x+9 = 0
  • SUM of the ROOTS = \sf\dfrac{3}{5}

To find :-

Solution:-

\implies \sf\dfrac{-(-3)}{k} = \sf\dfrac{3}{5}

\implies \sf K = \sf\dfrac{3×5}{3}

\implies \sf K = 5

Now, product of roots = c/a

\implies \sf product \:of \:zeroes = \sf\dfrac{9}{5}


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