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The sum of the remainders obtained when \left(x^{3}+(k+8) x+k\right) is divided by (x- 2) or when it is divided by (x+1) is zero. FInd the value of k. |
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Answer» f(x)=x^3+(k+8)x+k,g(x)= x-2h(x)= x+1Take x-2=0 x=2f(2)=8+(k+8)2+k =8+2k+16+k =24+3k Take x+1=0 x=-1 f(-1)=-1+(k+8)(-1)-5 =-1-k-8+k =-9 Now, add the remainders 3k+24-9=03k+15=0k=-5 Can you solve this question in another way,I mean without using functions? according to standard of class 8 cbse pls. |
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