The sum of the radius of the base and height of a solid cylinder is 37

1.	The sum of the radius of the base and height of a solid cylinder is 37 m. If the total surface area of the solid cylinder is 1628 m2, find the circumference of its base.
Answer» We have, Sum of base radius and height of cylinder = 37m (r + h) = 37m Total surface area = 1628 m² By using the formula, Total surface area = 2πr(h+r) So, 2πr(h+r) = 1628 2 × 22/7 × r (37) = 1628 r = 1628×7 / 2× 22×37 = 11396 / 1628 = 7m ∴ Circumference of its base = 2πr = 2 × 22/7 × 7 = 44 m

The sum of the radius of the base and height of a solid cylinder is 37 m. If the total surface area of the solid cylinder is 1628 m2, find the circumference of its base.

Answer»

We have,

Sum of base radius and height of cylinder = 37m

(r + h) = 37m

Total surface area = 1628 m²

By using the formula,

Total surface area = 2πr(h+r)

So,

2πr(h+r) = 1628

2 × 22/7 × r (37) = 1628

r = 1628×7 / 2× 22×37

= 11396 / 1628

= 7m

∴ Circumference of its base = 2πr

= 2 × 22/7 × 7

= 44 m