1.

The sum of the numerator and denominator of a fraction is 4 more than twice the numerator. If the numerator and denominator are increased by 3. They are in the ratio of 2: 3. Determine the fraction.

Answer»

Let the required fraction be x/y . 

As per the question 

x + y = 4 + 2x 

⇒ y – x = 4 ……(i) 

After changing the numerator and denominator 

New numerator = x + 3 

New denominator = y + 3 

Therefore x+3/ y+3 = 2/3 

⇒3(x + 3) = 2(y + 3) 

⇒3x + 9 = 2y + 6 

⇒ 2y – 3x = 3 ……(ii) 

Multiplying (i) by 3 and subtracting (ii), we get: 

3y – 2y = 12 – 3 

⇒y = 9 

Now, putting y = 9 in (i), we get: 

9 – x = 4

⇒ x = 9 – 4 = 5 

Hence, the required fraction is 5/9 .



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