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the sum of the numerator and denominator of a fraction is 4 more than twice the numerator if the numerator and denominator increased by 3 they are in the ratio 2 : 3 determine the fraction in elimination method |
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Answer» Answer: Let the numerator be n and the denominator be d ATQ n+d = 2n+4 => d= 2n + 4 -n => d= n+4 n+3/d+3 = 2/3 => n+3 * 3 = 1 => 3N+9 = 2d + 6 d+3 2 n + 4 . = d + 0 3n + 9 . = 2d + 6 Multiply by 3 3n + 12 = 3d + 0 3n + 9 . = 2d + 6 - - - - __________________________________ 3 = d - 6 => d=9 => n=5 Therefore the FRACTION is 5/9
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