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The sum of the first p terms of a sequence is p(p+ 1) (p+2). The 10 term of the sequence is(A) 396(B) 600(C) 114(D) 330 |
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Answer» sum of p terms=p (p+1)(p+2)S1 be sum of 1 termS1=a1=1 (1+1)(1+2)=6S2 be sum of 2 termsS2=a1+a2=2 (2+1)(2+2)=24 a2=24-a1=24-6=18 d=a2-a1=18-6=12a10=a+9d=6+9×12=6+108=114a10=114 |
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