1.

the sum of the digits of a two digit number is 9 also nine times this number is twice the number obtained by reversing the order of the digits find the number

Answer»

Let  two digit number be 10x + y

sum of two digit = x+y = 9 

reversed number = 10y+x

according to q.

9(10x + y) = 2(10y + x)

90x + 9Y = 20X + 2y

88x  =  11y

8x = y

putting value in x  + y = 9

x+ 8x =9

9x = 9

 x = 1 

y  = 9 - x

y  = 8

number is 10x + y

10 + 8

18 



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