The sum of the digits of a two digit number is 8. The number formed on

1.	The sum of the digits of a two digit number is 8. The number formed on reversing theorder of the digits is 36 more than the original number. Find the number.
Answer» Step-by-step explanation: let the tens digit number be 'a' and ones digit number be 'b' a + b = 8 ( GIVEN ). - A 10a + b + 36 = 10B + a 9b - 9a = 36 b - a = 4 - B by A + B we GET 2b = 12 b = 6 a = 2 so the numbers are 26 and 62

The sum of the digits of a two digit number is 8. The number formed on reversing theorder of the digits is 36 more than the original number. Find the number.

Answer»

Step-by-step explanation:

let the tens digit number be 'a' and ones digit number be 'b'

a + b = 8 ( GIVEN ). - A

10a + b + 36 = 10B + a

9b - 9a = 36

b - a = 4 - B

by A + B we GET

2b = 12

b = 6

a = 2

so the numbers are 26 and 62

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The sum of the digits of a two digit number is 8. The number formed on reversing theorder of the digits is 36 more than the original number. Find the number.​

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The sum of the digits of a two digit number is 8. The number formed on reversing theorder of the digits is 36 more than the original number. Find the number.