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.The sum of the digits of a 2-digit number is 10. The digit in one's place is nine times the digit atten's place. Find the number, |
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Answer» Answer: 91 Step-by-step explanation: LET the DIGIT at TEN's PLACE be x digit at one's place be 9x According to question, 9x+x=10 10x=10 x=1 therefore one's digit=9x=9 ten's digit=x=1 number=91 |
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