1.

.The sum of the digits of a 2-digit number is 10. The digit in one's place is nine times the digit atten's place. Find the number,​

Answer»

Answer:

91

Step-by-step explanation:

LET the DIGIT at TEN's PLACE be x

digit at one's place be 9x

According to question,

9x+x=10

10x=10

x=1

therefore one's digit=9x=9

ten's digit=x=1

number=91



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