1.

the sum of the digit of a two digit number is 12 the number obtained by interchanging its digits exceeds and given number by 18 find the numbers

Answer»

Let the no. be 10x + y

x + y = 12 eq1

10y + x = 10x + y + 18

9x - 9Y = -18

x - y = -2 eq2

Solve eq1 and eq2

2x = 10

x = 5

put VALUE of x in eq1

5 + y = 12

y = 7

Hence no. is 10x + y

10 × 5 + 7

57

Thanks



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