1.

the sum of the digit of a 2 digit number is 10. the number obtained by interchanging the digits exceeds the original number by 36 . find the original number .​

Answer»

original number=XY

their SUM, x+y=10...........(1)

on interchanging the number

(10y+x)=(10x+y)+36

9y-9x=36

y-x=4........................(2)

ADDING (1) & (2) we get

2y=14

y=7

putting the value of y in (1) we get

x=3

the original number is xy i.e. 37

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