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The sum of the 3 terms of a arithematic sequence is 45 if the product of the first and 3rd terms exceeds the 2nd term by 41.find the arithematic sequence? |
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Answer» a+a+d+a+2d=45 3a+3d=45 a+d=15 Given...a(a+2d)-(a+d)=41 a^2+2ad-a-d=41 |
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