1.

The sum of the 3 terms of a arithematic sequence is 45 if the product of the first and 3rd terms exceeds the 2nd term by 41.find the arithematic sequence?​

Answer»

LET the TERMS be a,a+d,a+2d

a+a+d+a+2d=45

3a+3d=45

a+d=15

Given...a(a+2d)-(a+d)=41

a^2+2ad-a-d=41



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