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The sum of squares of two consecutive natural numbers is 164 . find the numbers |
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Answer» ONE number=X another number=X+2 x^2+(X+2)^2=164 x^2+x^2+4+4x-164=0 2x^2+4x-160=0 divide by 2 x^2+2x-80=0 x^2+10x-8x-80=0 X(X+10)-8(X+10)=0 (x-8)(X+10)=0 x-8=0. X+10=0 X=8. X=-10 €x=8 one number=X=8 another number=X+2=8+2=10 mark me as BRAINLIEST |
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