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The sum of squares of two consecutive integers is 145 |
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Answer» Let the FIRST no be=x+1 Let the second no be=x+2 The SUM of the numbers=145 x+1+x+2=145 x+x+1+2=145 2x+3=145 2x=145-3 2x=142 x=142/2 x=71 1st no=71+1=72 2nd no=71+2=73 thanks me mark as brainliest answer following me |
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