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The sum of four numbers is 48. When 5 and 1 are added to the first two and 3 & 7 are subtracted from the 3rd & 4th, the numbers will be equal. The numbers areA. ` 4, 12, 12, 20`B. ` 5,11, 13, 19`C. ` 6,10,14,18`D. ` 9,7,15, 17` |
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Answer» Correct Answer - C Let four numbers are a, b, c, d, then ` a + b+ c+d = 48` …(i) and a+5=b+1 …(ii) or, a = b - 4 ..(iii) and c -3 = d - 7 …(iv) c = d - 4 ..(v) Substituting equation (iii) and (v) in equation (i) we get ` b - 4 +b+d-4+d= 48` ` b +d = 28` (vi) But we know, b+1 = d - 7 ` :. b = d - 8` Substituting in equation (vi) we get ` d - 8 ne d = 28` d = 18 Solving this way we get a = 6, b = 10, c = 14 and d = 18 |
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