1.

The sum of four consecutive multiples of 4 is 120...... Find these multiples.....

Answer»

Let the SMALLEST multiple be x
so 2ND no.= x+4
3RD no.=x+8
4th no.= x+12
According to question
(x)+(x+4)+(x+8)+(x+12)= 120
4x+24=120
x=120-24/4
x=96/4
x=24
Therefore the MULTIPLES are 24,28,32,36



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