The sum of first three terms of GP is 13/12th and their product is -1,

1.	The sum of first three terms of GP is 13/12th and their product is -1,find the terms
Answer» Step-by-step explanation: let the FIRST 3 TEAMS of gp be a,a+d, a-d ACCORDING to question sum =13/12 3a=13/12 a=13/36 and product =-1 a(a+d) (a-d) (a^2-d^2)(a)= -1 a^3-ad^2=-1 d=-2.8

The sum of first three terms of GP is 13/12th and their product is -1,find the terms

Answer»

Step-by-step explanation:

let the FIRST 3 TEAMS of gp be

a,a+d, a-d

ACCORDING to question

sum =13/12 3a=13/12

a=13/36

and product =-1

a(a+d) (a-d)

(a^2-d^2)(a)= -1

a^3-ad^2=-1

d=-2.8

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The sum of first three terms of GP is 13/12th and their product is -1,find the terms​

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The sum of first three terms of GP is 13/12th and their product is -1,find the terms