The sum of first three terms in an arithmetic progression is 24 and th

1.	The sum of first three terms in an arithmetic progression is 24 and thesum of their squares is 224. Find the first three terms of this arithmeticprogression.
Answer» Answer: LET the roots of A.P .be (a-d) ,a,(a+d) Now the sum of 1ST three terms is 24 that means a-d+a+a+d=24 3a=24 a=8 we GOT the value of a=8 Now, squaring the terms (a-d) 2 +(a) 2+ (a-d) 2 =224 where 2 are square not in multiplication a2+d2-2ad+a2+a2+d2+2ad=224 3a 2 +2D 2 =224 3×8×8+2d2=224 2d2=224–192 2d2=32 d2=16 d=4 Therefore a-d,a,a+d are 8–4,8,8+4 4,8,12 ←This are the VALUES of 1st three 3terms

The sum of first three terms in an arithmetic progression is 24 and thesum of their squares is 224. Find the first three terms of this arithmeticprogression.

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Answer:

LET the roots of A.P .be (a-d) ,a,(a+d)

Now the sum of 1ST three terms is 24 that means

a-d+a+a+d=24

3a=24

a=8

we GOT the value of a=8

Now,

squaring the terms

(a-d) 2 +(a) 2+ (a-d) 2 =224

where 2 are square not in multiplication

a2+d2-2ad+a2+a2+d2+2ad=224

3a 2 +2D 2 =224

3×8×8+2d2=224

2d2=224–192

2d2=32

d2=16

d=4

Therefore a-d,a,a+d are

8–4,8,8+4

4,8,12 ←This are the VALUES of 1st three 3terms

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The sum of first three terms in an arithmetic progression is 24 and thesum of their squares is 224. Find the first three terms of this arithmeticprogression.​

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The sum of first three terms in an arithmetic progression is 24 and thesum of their squares is 224. Find the first three terms of this arithmeticprogression.