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| 1. |
The sum of first three term of gp is 39/10and their product is 1. The common ratio and the terms |
| Answer» Let three terms of a.p be a/r,a,ar AtoQa/r+a+ar=39/10 eq.1Also a/r.a.ar=1a^3=1a=1 Now put this value of a in eq.1,we get1/r+1+r=39/101+r+r^2/r=39/1010+10r+10r^2=39r10^2r+10r-39r+10=010^2r-29r+10r=010^2r-25r-4r+10=05r(2r-5)-2(2r-5)=0(5r-2)(2r-5)r=2/5or5/2 | |