The sum of first n term of an ap is 5n^2- 3n find the AP and hence fin

1.	The sum of first n term of an ap is 5n^2- 3n find the AP and hence find its 12th term.
Answer» Putting n=1, 5n²-3n Putting n=1, 5n²-3n=5-3=2 Putting n=1, 5n²-3n=5-3=2Putting n=2, 5n²-3n Putting n=1, 5n²-3n=5-3=2Putting n=2, 5n²-3n=14 Putting n=1, 5n²-3n=5-3=2Putting n=2, 5n²-3n=14Therefore 2ND term is 14-2=12 Putting n=1, 5n²-3n=5-3=2Putting n=2, 5n²-3n=14Therefore 2nd term is 14-2=12Therefore AP is 2, 12, 22 ... and so on. Putting n=1, 5n²-3n=5-3=2Putting n=2, 5n²-3n=14Therefore 2nd term is 14-2=12Therefore AP is 2, 12, 22 ... and so on.10th term=a+9d *Putting n=1, 5n²-3n=5-3=2Putting n=2, 5n²-3n=14Therefore 2nd term is 14-2=12Therefore AP is 2, 12, 22 ... and so on.10th term=a+9d=2+910 Putting n=1, 5n²-3n=5-3=2Putting n=2, 5n²-3n=14Therefore 2nd term is 14-2=12Therefore AP is 2, 12, 22 ... and so on.10th term=a+9d=2+910=2+90* *Putting n=1, 5n²-3n=5-3=2Putting n=2, 5n²-3n=14Therefore 2nd term is 14-2=12Therefore AP is 2, 12, 22 ... and so on.10th term=a+9d=2+910=2+90=92**

The sum of first n term of an ap is 5n^2- 3n find the AP and hence find its 12th term.

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