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The sum of first 5 multiples of 3 is:\xa0* |
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Answer» 45 Sum of first 5 multiples of 3:Sum of an AP is:\xa0n/2 \u200b×(2a+(n−1)d)a=3,d=3,n=5Then,\xa0Sum =\xa05/2 \u200b×(2×3+(5−1)×(3))=\xa05/2\u200b×(6+12)=\xa045 |
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