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The sum of first 15 term 3,7,11...... |
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Answer» Step-by-step explanation: 3,7,11... forms an A.P. With common difference = 7-3=4 Sum of N terms of A.P.= n/2[2a+(n-1)d] we have : a= 3 d=4 n=15 substituting VALUES in formula we get 15/2[2×3+(15-1)4] by solving this we got SUM = 420 |
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