1.

The sum of first 15 term 3,7,11......

Answer»

Step-by-step explanation:

3,7,11... forms an A.P.

With common difference = 7-3=4

Sum of N terms of A.P.= n/2[2a+(n-1)d]

we have :

a= 3

d=4

n=15

substituting VALUES in formula we get

15/2[2×3+(15-1)4]

by solving this we got

SUM = 420



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