The sum of digits in 2 digit no is 12 if we add 18 digits are reverse�

1.	The sum of digits in 2 digit no is 12 if we add 18 digits are reverse
Answer» Let us assume x and y are the two digits of the number Therefore, two-digit number is = 10x + y and the reversed number = 10Y + x Given: x + y = 12 y = 12 – x -----------1 Also given: 10y + x - 10x – y = 18 9y – 9X = 18 y – x = 2 -------------2 Substitute the value of y from EQN 1 in eqn 2 12 – x – x = 2 12 – 2x = 2 2x = 10 x = 5 Therefore, y = 12 – x = 12 – 5 = 7 Therefore, the two-digit number is 10x + y = (105) + 7 = 57 please mark me as the brainliest and click thanks*

The sum of digits in 2 digit no is 12 if we add 18 digits are reverse

Answer»

Let us assume x and y are the two digits of the number

Therefore, two-digit number is = 10x + y and the reversed number = 10Y + x

Given:

x + y = 12

y = 12 – x -----------1

Also given:

10y + x - 10x – y = 18

9y – 9X = 18

y – x = 2 -------------2

Substitute the value of y from EQN 1 in eqn 2

12 – x – x = 2

12 – 2x = 2

2x = 10

x = 5

Therefore, y = 12 – x = 12 – 5 = 7

Therefore, the two-digit number is 10x + y = (10*5) + 7 = 57

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