the sum of a two digit number is 12 if the digits are reversed the new

1.	the sum of a two digit number is 12 if the digits are reversed the new number becomes 4 by 7 times the original number find the original number
Answer» Answer: Step-by-step explanation: here you go ☆☆ ▪let DIGIT at ones place = x and at tens place= y ▪so, no. is 10Y + x ▪given, y+x= 12------《1》 ▪if no. is reversed , then ▪10x+ y = 4/7(10y +x) ▪10x-4/7x + y -40/7y 66/7x-33/7y = 0 ▪MULTIPLY term with 7 , we get , ▪66x -33y = 0 taking 33 as common, ▪2x -y =0------《2》 ▪by ELIMINATION method, multiply 1 by 2 and subtract 2 from 1 ,we get, ▪2x +2y =24 ▪2x - y = 0 - + - ▪3y = 24 ▪y = 8 ▪so x= 4 ▪so ORIGINAL no.= 84 hope it helps you....

the sum of a two digit number is 12 if the digits are reversed the new number becomes 4 by 7 times the original number find the original number

Answer»

Answer:

Step-by-step explanation:

here you go ☆☆

▪let DIGIT at ones place = x

and at tens place= y

▪so, no. is 10Y + x

▪given, y+x= 12------《1》

▪if no. is reversed , then

▪10x+ y = 4/7(10y +x)

▪10x-4/7x + y -40/7y

66/7x-33/7y = 0

▪MULTIPLY term with 7 , we get ,

▪66x -33y = 0

taking 33 as common,

▪2x -y =0------《2》

▪by ELIMINATION method,

multiply 1 by 2 and subtract 2 from 1 ,we get,

▪2x +2y =24

▪2x - y = 0

- + -

▪3y = 24

▪y = 8

▪so x= 4

▪so ORIGINAL no.= 84

hope it helps you....