1.

the sum of a two digit number and the number obtained by reversing the order of its digits is 99. if digits differ by 3. find the number

Answer»

Let the digits are x and y so..
If i write a no. xy then= 10x + y
e.g. 32= 10×3+2
so.. REVERSING of xy is yx and
yx=10y+x

Now..
A/Q : x-y=3 eq1
10x+ y+ 10y+x = 99 eq 2
so from eq 2
10x+y+10y+x= 99
11x+11y=99
x+y=9 ...... eq 3

Now
from eq 1
we have
x-y=3
x=3+y
substituing VALUE of x in eq 3
x+y=9
3+y+y=9
2y=6
y=3
Substituting value of y in eq1
x-y=3
x-3=3
x=6
so the no. is 36 or 63
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