The sum of a two digit number and the number obtained by reversing the

1.	The sum of a two digit number and the number obtained by reversing the order of its digits is121 and the two digits difer by 3. Find the number.
Answer» Step-by-step explanation: $/\Huge\fbox{\color{red}{Answer:-}}$ Let the units digit be y let the tens digit be X number = 10X + y On reversing the digits , the no.becomes 10y + x 10x + y + 10y + x = 121 11x + 11y = 121 11(x+y) = 121 x + y = 121/11 x + y = 11 -----------(1) Given,DIFFERENCE of digits = 3 x - y = 3 ------------(2) Adding both equations,(elimination method) x + y = 11 x - y = 3 --------------- 2x = 14 x = 14/2 x = 7 put x = 7 in equation (1) 7 + y = 11 y = 11-7 y = 4 Number = 10x + y Number = 10(7)+4 Number = 70 + 4 Number = 74 HOPE IT HELPS...

The sum of a two digit number and the number obtained by reversing the order of its digits is121 and the two digits difer by 3. Find the number.

Answer»

Step-by-step explanation:

$/\Huge\fbox{\color{red}{Answer:-}}$

Let the units digit be y

let the tens digit be X

number = 10X + y

On reversing the digits , the no.becomes 10y + x

10x + y + 10y + x = 121

11x + 11y = 121

11(x+y) = 121

x + y = 121/11

x + y = 11 -----------(1)

Given,DIFFERENCE of digits = 3

x - y = 3 ------------(2)

Adding both equations,(elimination method)

x + y = 11

x - y = 3

---------------

2x = 14

x = 14/2

x = 7

put x = 7 in equation (1)

7 + y = 11

y = 11-7

y = 4

Number = 10x + y

Number = 10(7)+4

Number = 70 + 4

Number = 74

HOPE IT HELPS...