1.

The sum of 5 consecutive integers is 505 what is the third number in this sequence

Answer»

USING ALGEBRA:

N+(n+1)+(n+2)+(n+3)+(n+4)=505

5n+10=505

5n=505-10

5n=495

n=495/5

n=99

n+1=100

n+2=101 answer

using simple arithmetic:

505/5 gives the mean of the NUMBERS and ALSO the middle number which is the third number that you want

505/5=101


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