The sum of 3 consecutive terms of an A.P. is 48. The productof its fir

1.	The sum of 3 consecutive terms of an A.P. is 48. The productof its first and the last term is 252Âˇ d=
Answer» Let three consecutive terms of an AP be ( A - D ) , A and ( A + D ). According to the question Sum of three consecutive terms = 48 A - D + A + A + D = 48 3A = 48 A = (48/3) = 16. First term ( A ) = 16. Again, Product of first term and last term = 252 ( A - D ) × ( A + D ) = 252 ( A)² - ( D)² = 252 (16)² - ( D )² = 252 (D)² = 256 - 252 D² = 4 D = ✓4 = 2 Hence, Common difference ( D ) = 2. Like my answer if you find it useful!

The sum of 3 consecutive terms of an A.P. is 48. The productof its first and the last term is 252Âˇ d=

Answer»

Let three consecutive terms of an AP be ( A - D ) , A and ( A + D ).

According to the question

Sum of three consecutive terms = 48

A - D + A + A + D = 48

3A = 48

A = (48/3) = 16.

First term ( A ) = 16.

Again,

Product of first term and last term = 252

( A - D ) × ( A + D ) = 252

( A)² - ( D)² = 252

(16)² - ( D )² = 252

(D)² = 256 - 252

D² = 4

D = ✓4 = 2

Hence,

Common difference ( D ) = 2.

Like my answer if you find it useful!