1.

The sum and product of 2 numbers are 12 and 35 respectively the sum of their reciprocal is?

Answer»

Step-by-step explanation:

LET the two numbers =a,B.

a+b=12 ...I.

ab=35. ...ii.

a=12-b ...iii

Substituting this value of b in ii

(12-b)×b=35.

12b-b²=35.

0=b²-12b+35

0=b²-5b-7b+35

0=b(b-5)-7(b-5)

0=(b-5)(b-7)

0=(b-5)

0=(b-7)

b=5

b=7

Taking value of b as 5.

Substituting this value of b in I.

a+5=12

a=12-5

a=7

So 1/a+1/b =1/7+1/5=(5+7)/35=12/35.

Taking value of b as 7.

Substituting this value of b in I.

a+7=12.

a=12-7.

a=5.

So 1/a+1/b=1/5+1/7=(7+5)/35=12/35.

I HOPE this helps you and BDW my NAME is Souvik DAS.



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