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The sum and product of 2 numbers are 12 and 35 respectively the sum of their reciprocal is? |
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Answer» Step-by-step explanation: a+b=12 ...I. ab=35. ...ii. a=12-b ...iii Substituting this value of b in ii (12-b)×b=35. 12b-b²=35. 0=b²-12b+35 0=b²-5b-7b+35 0=b(b-5)-7(b-5) 0=(b-5)(b-7) 0=(b-5) 0=(b-7) b=5 b=7 Taking value of b as 5. Substituting this value of b in I. a+5=12 a=12-5 a=7 So 1/a+1/b =1/7+1/5=(5+7)/35=12/35. Taking value of b as 7. Substituting this value of b in I. a+7=12. a=12-7. a=5. So 1/a+1/b=1/5+1/7=(7+5)/35=12/35. |
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