The straight lines x +y-0, 3x + y-4-0, x+3y-4-0from aAJísosceles(D) n

1.	The straight lines x +y-0, 3x + y-4-0, x+3y-4-0from aAJísosceles(D) none of these(B) equilateral(C) right angledints then locus of the po
Answer» Since none of the lines are perpendicular therefore it is not a right angled triangle. now find the intersection points of x+y=0, 3x+y-4=0, x+3y-4=0, we get(2,-2),(-2,2) & (1,1) let A(2,-2) B(-2,2), C(1,1) By distance formula we get AC=AB but not equal to AB Therefore it is a isoscels triangle.

The straight lines x +y-0, 3x + y-4-0, x+3y-4-0from aAJísosceles(D) none of these(B) equilateral(C) right angledints then locus of the po

Answer»

Since none of the lines are perpendicular therefore it is not a right angled triangle.

now find the intersection points of x+y=0, 3x+y-4=0, x+3y-4=0, we get(2,-2),(-2,2) & (1,1)

let A(2,-2) B(-2,2), C(1,1)

By distance formula we get AC=AB but not equal to AB

Therefore it is a isoscels triangle.