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The stopping potential in an experiment on photoelectric effect is 1.5 V. What is the maximum K.E. of the photoelectrons emitted ? |
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Answer» Solution :`K_max = eV_0 = 1.6 xx 10^(-!9) C xx 1.5 V` = 2.4`xx 10^(-19)` J or 1.5 eV. |
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