1.

The stopping potential in an experiment on photoelectric effect is 1.5 V. What is the maximum K.E. of the photoelectrons emitted ?

Answer»

Solution :`K_max = eV_0 = 1.6 xx 10^(-!9) C xx 1.5 V`
= 2.4`xx 10^(-19)` J or 1.5 eV.


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