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The stationary point of y=sinx are |
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Answer» Given : y = Sinx To find : STATIONARY point Solution: The stationary points will be the points where the gradient is zero: y = sinx dy/dx = Cosx Cosx = 0 for x = (2n + 1)π/2 n ∈ Z n = 0 => Sinπ/2 = 1 = (-1)⁰ n = 1 => Sin3π/2 = -1 = (-1)¹ n = 2 => Sin5π/2 = 1 = (-1)² Sin ( (2n + 1)π/2 ) = (-1)ⁿ Hence stationary point is ( (2n + 1)π/2 , (-1)ⁿ ) LEARN more: the line through A (4, 7) with gradient m meets the x-axis at P and ... Work out the equation of the line which has a gradient of 3 and ... |
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