1.

The standard heats of formation of CH_(4), H_(2)O and CH_(3)OHare -76, -242 and -266 kJ/mole respectively. The enthalpyCH_(3)OH_((l))+H_(2(g))rarrCH_(4(g))+H_(2)O_((l))

Answer»

`-4 kJ//"MOLE"`
`-556 kJ//"mole"`
`-318 kJ//"mole"`
`-52 kJ//"mole"`

SOLUTION :`DeltaH=SigmaDeltaH_(F)^(@)" (Product)"-SigmaDeltaH_(f)^(@)" (reactants)"`
`DeltaH=(-242-76)-(-266+0)=-52 kJ`.


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