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The standard Gibbs energy change for a gaseous reaction at 27 is X Kcal. If equilibrium constant a reaction is 100 and R is 2 cal K−1 mol−1. Then X is: |
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Answer» ΔGo=−RT lnK ∴X = −2 × 300 × ln 100 ∴ X = −2.7636 K cal |
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