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The standard emf of the cell `Zn+Cu^(2+)rarrCu+Zn^(2+)` is 1.10V at `25^(@)c` the emf of the cell when 0.1 M `Cu^(2)+` and 0.1 M `Zn^(2+)` solution are used will beA. 1.10VB. 0.110VC. `-1.10V`D. `-0.1 10V` |
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Answer» Correct Answer - A `E_("cell")=E_("cell")^(@)-(0.059)/(2)"log"([Zn^(2+)])/([Cu^(2+)])` `=1.10-(0.059)/(2)"log"(0.1)/(0.1)` =1.10V |
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