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The square of two positive integers differ by 4040 .Find their maximum possible sum |
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Answer» ong>ANSWER: bigger number = x = 10 smaller number = y = 6 Step-by-step explanation: bigger number = x smaller number = y
x2 + y2 = 136
x -y =4 x = y+4 (y+4)2 + y2 = 136
y2 + 8Y +16 +y2 = 136
2y2 + 8y - 120 = 0 y2 +4y - 60 =0
(y+10)(y-6)=0 y=-10 and y =6 we need positive number so y = 6 x = y+4=6+4 =10 bigger number = x = 10 smaller number = y = 6 |
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