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The square of a term in the arithmetic sequence 2, 5, 8, ……., is 2500. What is its position? |
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Answer» Let 2500 is the square of the nth term of the arithmetic sequence 2, 5, 8, …… xn = dn + (f - d) = 3n + (2 - 3) = 3n - 1 (3n - 1)2 = 2500 3n - 1 = 50 3n = 51 n = 17 It is the 17th term. |
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