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The speedometer readings of a car are shown below. Find the acceleration of the car and its displacement. Time Speedometer 9:25 am. 36 km/h 9:45 am 72 km/h |
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Answer» tion:Given:Time = t= 9.45 -9.25=20min= 20x60 secondsInitial velocity = 36km/h = 36x 5/18=10 m/sFinal velocity = V= 72km/h=72x 5/18=20m/sAcceleration= a=V-u/t=20-10/20x60=10/20x60=1/120=0.008m/s2THEREFORE acceleration of the car is 0.008m/s2From SECOND EQUATION of MOTION:V^2-u^2=2asS=V^2-u^2/2aS=(20×20)-(10×10)/2*0.008S=(400_100)/2*0.008=300/2×0.008 =150/0.008 =150*1000/8 =18.75x 1000 =1875000/100=18750m Magnitude of DISPLACEMENT is 18750mthanks mark me as brilliant |
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