1.

The speed with which a bullet can be fired is 150 ms^(-1). Calculate the greatest distance to which it can be projected and also the maximum height to which it would rise.

Answer»

Solution :`R = (u^(2) sin 2 ALPHA)/(G) = ((150)^(2) sin 90^(@))/(9.8) = 2295.1m`
`H_("max") = (u^(2) sin^(2) alpha)/(2g) = ((150)^(2) sin^(2) 45^(@))/(2 xx 9.8) = 573.97 m`


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