1.

The speed of electron in the first Bohr orbit is C/(137), where C is speed of light in free space. The speed of electron in the 2nd Bohr orbit will be:

Answer»

`1/2 ((C)/(137))`
`2 xx ((C)/(137))`
`1/4 ((C)/(137))`
`A((C)/(137))`

SOLUTION :`mv r_(n)=(NH)/(2PI), v=(nh)/(2pi mr_(n))`
Put `r_(n) alpha n^(2)`
`v alpha 1/n`
`v_(2)=v_(1)/2=1/2 ((c)/(137))`


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